effluent pump [RE-wrenches]

matthew tritt solarone at charter.net
Fri Mar 28 09:49:01 PST 2003


Windy,

Since there's no way to effectively separate the many splendid things
endemic to sewage effluent (short of burning it) any pump used to pump it
MUST have the capacity to grind big stuff into little stuff. I know this to
be true, having had the opportunity of hands-on experience in this field for
a number of years. :-(
With a tiny 100 gallon tank you can be sure that there will be plenty for a
sewage ejection pump to chew on.

Matt T
----- Original Message -----
From: "Windy Dankoff, Dankoff Solar" <windy at dankoffsolar.com>
To: <RE-wrenches at topica.com>
Sent: Friday, March 28, 2003 8:33 AM
Subject: Re: effluent pump [RE-wrenches]


> >Greetings all,
> >
> >I have an off-grid customer who has a 200 foot head to pump effluent to
> >with an ejector pump.  The one the plumber specified uses 10 amps at
> >220vac.  Anyone heard of something more efficient, possibly at 120vac?
> >He said his tank was only going to be about 100 gallons (could this be?)
> >and that it would probably cycle about three times a day.
> >
> >Any thoughts greatly appreciated -- Kurt Nelson
>
>
>
>
>
> If the water is not full of large solids, but is settled, check out
> our Solar Force Piston Pump, available in 12/24/48VDC and 115VAC. It
> will pass particles the size of coarse sand, if necessary.
>
> Model 3020 will push 4.8 GPM at 200 feet, drawing 308 watts. AC model
> draws about 10% more, not including inverter loss.
>
> ref:
>
http://dankoffsolar.com/cgi-bin/siteman/page.cgi?g=Solar_Water_Pumps%2FSurfa
ce_Pumps%2Findex.html&d=1
>
> For evaluating pumping options, I suggest you use the formula I've
> pasted below (from our web site, reference section). For AC, estimate
> the power draw of the inverter to meet the pump load.
>
> I hope this helps.
>
> Windy
>
> ============================
>
> DETERMINE POWER REQUIRED TO PUMP WATER
>
> This is useful for estimating the cost and feasibility of any pumping
> system, even if the specific pump is unknown.
>
> WATTS=  ( FEET X GPM X 18.8 )  /  PUMP EFFICIENCY %
>
> Feet or Meters = Total Dynamic Head
> Pump Efficiency is "wire to water" (includes motor and pump losses)
> Average efficiency for solar pumps is ~ 45% (varies 30 to 60%)
> For a conventional AC pump, it is ~35% (varies widely)
> Enter Efficiency as a whole number: For 45% enter "45"
>
> TO DETERMINE THE EFFICIENCY of a proposed or existing pump system, invert
> the above equation to solve for pump efficiency.
>
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