[RE-wrenches] Percent of DC capacity that is inverted to AC kWh?

[Christopher Warfel]

Hi Dan, Sorry for the confusion.

Maybe an example would help.  Take a 2000 w dc multimode system that is 
coupled with a 3600 w ac rated multimode inverter.  What percentage of 
the dc capacity is inverted into ac capacity.  So, roughly 2000 x .9 
(wiring and similar losses from array to battery) x .95 for an assumed 
5% usage to charge/float the batteries x .98 for dc to ac inverter 
efficiency makes me think that 2000 x .9 x .95 x .98 * (4.5 x 365) 
yields = 2,752 kWh annually. The utility is assuming roughly 3600 x .98 
x (4.5 x 365) {if they are assuming anything at all} = 5,368 kWh revenue 
lost. The regulatory assumption overestimates the capacity factor by @49%.

I'll post to the WRENCHES too to help clarify hopefully.   Chris

On 8/28/2019 9:10 AM, Dan Lepinski, P.E. wrote:
> OFF-LINE REPLY
>
> Hello Chris,
>
> The wording of your question is confusing.  You ask about the percentage of DC capacity vs AC power output, then add batteries into the mix.
>
> What system topology is the focus of your query?
>
> I'll be glad to do what I can to assist.  Just need clear direction on the configuration.
>
>
> Regards,
>
>
> Dan
>