<div dir="ltr"><div><div><div><div><div><div><div>Hi Eric,<br><br></div>We did work together at APS. I hope life has been treating you great. <br><br></div>We do have a commercial design guide which can help you with all of your questions. Feel free to reach out to me directly with any specific questions You may have. The design guide is available at on our website under downloads, technical briefs, Commercial System Design with M215s. You should be able to find it at; <a href="http://enphase.com/global/resources/geo_us/" target="_blank">http://enphase.com/global/resources/geo_us/</a>. The document should also be attached.<br>
<br></div>As Nathan mentions, a three-phase system's current calculation includes a √3 factor (1.732). I find the easiest way to calculate the current in a three-phase system is;<br></div>Amperage = # of microinverters * 215w / 208 / 1.732<br>
<br></div>So the current for a system with 25 M215s would be calculated at 14.92A. There is an additional 1.25 safety factor for the over-current protection device, of course.<br></div>25 * 215w / 208 / 1.732 = 14.92A x 1.25 = 18.64A. <br>
<br></div><div><div><div><div><div><div><div><div> <br></div></div></div></div></div></div></div></div><div class="gmail_extra"><br><br><div class="gmail_quote">On Thu, Oct 3, 2013 at 11:52 AM, SunHarvest <span dir="ltr"><<a href="mailto:eric@harvesthesun.com" target="_blank">eric@harvesthesun.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex"><u></u>
<div bgcolor="#ffffff">
<div><font face="Arial">Hey Wrenches & Nick Soleil (with whom
I worked at APS for a time I believe...),</font></div>
<div><font face="Arial"></font> </div>
<div><font face="Arial">I'm not familiar with Enphase commercial
applications and am currently working through a commercial design. Enphase, on
their M215 datasheets claim up to 25 micros per branch, at 1.0A each, with
each branch terminating at a 20A breaker. By my calculations, 25 micros at 1.0A
each (25A*1.25=31.25A) need to terminate at a 40A breaker. Anyone know what I'm
missing or know how the 20A breaker design gets past the
AHJ?</font></div>
<div><font face="Arial"></font> </div>
<div>Eric Stikes<span><font color="#888888"><br>SunHarvest</font></span></div><span><font color="#888888">
<div><a href="tel:%28530%29%20798-3738" value="+15307983738" target="_blank">(530) 798-3738</a></div></font></span></div>
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<br></blockquote></div><br><br clear="all"><br>-- <br><p style="margin:0in 0in 0.0001pt"><span style="font-size:14pt">Cordially,</span></p><p style="margin:0in 0in 0.0001pt"><b><span style="font-size:14pt">Nick Soleil</span></b><span style="font-size:14pt"></span></p>
<p style="margin:0in 0in 0.0001pt"><b><span>Field Applications Engineer<br></span></b></p>
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