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<DIV><SPAN class=687453900-21092010><FONT face=Arial>The only potential problem
I see might be from one unbalanced string, shading for instance.
</FONT></SPAN></DIV>
<DIV><SPAN class=687453900-21092010><FONT face=Arial>Otherwise the
4 <2%r strings feeding back thru a conductor with <1%r should be no
problem.</FONT></SPAN></DIV>
<DIV><SPAN class=687453900-21092010><FONT face=Arial>What could possibly go
wrong....</FONT></SPAN></DIV>
<DIV><SPAN class=687453900-21092010><FONT face=Arial>Jim</FONT></SPAN></DIV>
<BLOCKQUOTE dir=ltr style="MARGIN-RIGHT: 0px">
<DIV class=OutlookMessageHeader dir=ltr align=left><FONT face=Tahoma
size=2>-----Original Message-----<BR><B>From:</B>
re-wrenches-bounces@lists.re-wrenches.org
[mailto:re-wrenches-bounces@lists.re-wrenches.org]<B>On Behalf Of </B>Hans
Frederickson<BR><B>Sent:</B> Monday, September 20, 2010 6:52 PM<BR><B>To:</B>
'RE-wrenches'<BR><B>Subject:</B> Re: [RE-wrenches] fewer wires, mo
bettah?<BR><BR></FONT></DIV>
<DIV dir=ltr align=left><SPAN class=573574323-20092010><FONT face=Arial
color=#0000ff size=2>Marco,</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=573574323-20092010><FONT face=Arial
color=#0000ff size=2>In this case, slightly differing resistance between your
grounded and ungrounded conductors will not make any difference. You will just
need to do your DC voltage drop calculations for each half separately, instead
of the typical voltage drop calculation that uses wire length x 2. Different
resistance in parallel battery cables is an important issue, but that's
not what you're talking about.</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=573574323-20092010><FONT face=Arial
color=#0000ff size=2></FONT></SPAN> </DIV>
<DIV dir=ltr align=left><SPAN class=573574323-20092010><FONT face=Arial
color=#0000ff size=2>Regards,</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=573574323-20092010><FONT face=Arial
color=#0000ff size=2>-Hans</FONT></SPAN></DIV>
<DIV dir=ltr align=left><FONT face=Arial color=#0000ff size=2></FONT><FONT
face=Arial color=#0000ff size=2></FONT><FONT face=Arial color=#0000ff
size=2></FONT><FONT face=Arial color=#0000ff size=2></FONT><BR> </DIV>
<DIV class=OutlookMessageHeader lang=en-us dir=ltr align=left>
<HR tabIndex=-1>
<FONT face=Tahoma size=2><B>From:</B>
re-wrenches-bounces@lists.re-wrenches.org
[mailto:re-wrenches-bounces@lists.re-wrenches.org] <B>On Behalf Of </B>Marco
Mangelsdorf<BR><B>Sent:</B> Monday, September 20, 2010 11:08 AM<BR><B>To:</B>
'RE-wrenches'<BR><B>Subject:</B> [RE-wrenches] fewer wires, mo
bettah?<BR></FONT><BR></DIV>
<DIV></DIV>
<DIV class=Section1>
<P class=MsoNormal>Check this out.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Four series strings of mods on a same plane roof feeding a
larger Sunny Boy or Fronius inverter.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Four #10 conductors for the ungrounded, fused (at the
inverter) conductors. And for the grounded conductor, a single, common,
larger conductor from those four strings.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>So instead of four pairs of wires, or eight total, I’m
using just five (plus ground).<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Assuming that the larger grounded conductor is adequately
sized taking into account conduit fill and temp derate for exposed conduit,
does anyone see a problem in doing this?<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>I’ve already been doing this for several years with no
problems that I can tell. But it occurred to me whether different
resistances between the ungrounded conductors and the grounded conductor might
be an issue.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Feedback appreciated.<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P>
<P class=MsoNormal>Thanks,<o:p></o:p></P>
<P class=MsoNormal>marco<o:p></o:p></P>
<P class=MsoNormal><o:p> </o:p></P></DIV></BLOCKQUOTE></BODY></HTML>